x^2+12x=160

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Solution for x^2+12x=160 equation:


Simplifying
x2 + 12x = 160

Reorder the terms:
12x + x2 = 160

Solving
12x + x2 = 160

Solving for variable 'x'.

Reorder the terms:
-160 + 12x + x2 = 160 + -160

Combine like terms: 160 + -160 = 0
-160 + 12x + x2 = 0

Factor a trinomial.
(-20 + -1x)(8 + -1x) = 0

Subproblem 1

Set the factor '(-20 + -1x)' equal to zero and attempt to solve: Simplifying -20 + -1x = 0 Solving -20 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '20' to each side of the equation. -20 + 20 + -1x = 0 + 20 Combine like terms: -20 + 20 = 0 0 + -1x = 0 + 20 -1x = 0 + 20 Combine like terms: 0 + 20 = 20 -1x = 20 Divide each side by '-1'. x = -20 Simplifying x = -20

Subproblem 2

Set the factor '(8 + -1x)' equal to zero and attempt to solve: Simplifying 8 + -1x = 0 Solving 8 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1x = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1x = 0 + -8 -1x = 0 + -8 Combine like terms: 0 + -8 = -8 -1x = -8 Divide each side by '-1'. x = 8 Simplifying x = 8

Solution

x = {-20, 8}

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